全國中小學科展

未得獎作品

數列生成遞迴

這個題目是源自2003年的TRML思考賽的題目,原題目並不難,它只有用到簡單的排列方法,主要是討論 an 、bn 兩種數字的排列,其中 an 為滿足下列所有條件之N位數A的個數。 I. A中每一個數字為1或2 II. A中至少有相鄰的兩數字是1 而 bn 表示滿足下列所有條件的N位數B的個數 I. B中每一個數字為0或1 II. B中至少有相鄰的兩數字是1 以及探討an 、bn 與費氏數列cn之關係,其中 cn = cn-1 + cn-2 ,n≧3 ,c1=1, c2=2 。 其中 an 如果改成考慮為一數列,其值不變;而 bn 如果改為數列,那麼就不需要考慮0不能為首位數字的情況。如此,讓人聯想到一個用生成函數解的題目「一個N項數列,其中每一項只能是0或1或2,其中0和2永不能相鄰,求這個數列個數的一般式。」,因此,我們嘗試將這個題目改變它的要求繼續做下去,發現其中有某些規則,例如:不只是原來的11相鄰,甚至是排列其它種方式,都可能從其遞迴式看出它排列的意義,甚至這種排列數是可以用遞迴式求出來的。這提供了我們另一種求數字排列的方法,也是我們覺得有趣的地方。 在過程中我們初步得到以下結論: This solution is according to power contest of 2003 TRML. It is composed of two number arrangements, an , bn . First, suppose an is the total number conforming to the following rules. I. Each number is 1 or 2 in A. II. There is a couple of (11) in A at least. Then, suppose bn is the total number conforming to the following conditions. I. Each number is 0 or 1 in B. II. There is a couple of (11) in B at least. Furthermore , we give the thought to the relation among an , bn ,and cn (Fibonacci Sequence). By the way, if an is changed to a sequence, and the result is the same. But if bn is to arrange number, we have to give thought to the fact that the first number can’t be zero. If it is a sequence, we don’t have to consider it. The problem belongs to combinatorics. After we do this problem, we find not only original question but also other permutation can be understood by its formula. The problem provides us with other means to solve permutation and combination question. Then, we get the conclusion as follows:

電離轉輪

This research primarily aims to observe how does the electric work, why does it work and the relationship between the surrounding circumstance and the repulsive torque. The electric whirl is made of an enameled wire bent into right angle with sharpened ends. When an AC high voltage is applied, the electric field intensity around the whirl ends is strong due to the small curvature radius of the ends. The molecules in air at both ends are ionized. This cause the phenomenon of point discharge. The positive and negative ions produced by alternating current forms AC ion wind, and produce a torque to make the whirl rotate. The object of this experiment is to observe the relationship between the surrounding circumstance and the torque repulsion. We design an apparatus to measure the angular velocity of the rotating whirl. We also calculated the kinetic energy of the whirl and the work done by the torque. The repulsive torque can be obtained by Work energy theorem. Result: (1)The angular velocity of the electric whirl is direct ratio to repulsive torque. When we want to find out the relationship between the manipulate reason and the repulsive torque, we can just compare the angular velocity with the manipulate reason. (2)The angular velocity of the electric whirl is only related to the peak voltage, and it does not make difference whether we apply AC high voltage and DC high voltage. (3)When the humidity is over 68%, the electric whirl cannot function normally. (4)Under the low-pressure circumstance, the electric whirl will rotate with glow discharge and the angular velocity will decrease to zero gradually.本實驗是探討電離轉輪的性質、原理與周圍環境的關係。「電離轉輪」為漆包線兩端折成直角並磨尖而成,接上交流高壓電源時,其尖端曲率半徑小,電場強度相對大,會游離尖端附近的空氣分子,產生尖端放電的現象,而交流電交替產生的正、負離子會形成交流離子風,並產生轉動力矩,使轉輪轉動。我們設計一個裝置,使其能偵測轉輪轉動的狀況,運用測得數據計算出轉動時的動能和作功狀況,套用功能定理便可求得轉輪通電時產生的斥力矩。實驗結果顯示(1)轉輪的角速度和尖端斥力矩成正相關,所以當我們想得知尖端斥力矩和實驗操縱變因的關係時,只要比較角速度和操縱變因就可以了,這簡化了原本繁複的計算和冗長的數據處理過程。(2)轉輪的角速度只和峰值電壓有關,和直流或交流沒有直接關係。(3)轉輪在超過溼度68%之後,就不會正常運作。(4)在低壓條件下,轉輪轉動時會伴隨淡紫色的輝光放電(glow discharge)現象,而抽氣塔中與轉輪尖端最接近的一點,也就是電場最強的一點,會和尖端同時產生光芒,相互輝映。

蝌蚪游泳能力之探討

本研究主要探討蝌蚪之游泳運動特性,及游泳速度(V)與尾鰭長度(SL)、尾鰭高度(SH)、身體質量(M)、尾鰭擺動頻率(TBF)、擺動幅度(AMP)之關係,並分析蝌蚪游泳之體軸變化及流場變化。祈能了解蝌蚪之游泳運動特性,進而探討其適應環境之機制。研究結果顯示:黑眶蟾蜍蝌蚪體重(M)愈重,則鰭長、鰭高亦隨之生長,並呈現高度相關性(R2=0.9381、R2=0.9809)。另外,尾鰭生長時之長度增加較多。蝌蚪體重(M)與鰭長(SL)、鰭高(SH)之迴歸方程式(M=0.027SL+0.342SH-0.078,R2=0.9832)。黑眶蟾蜍蝌蚪之游泳速度,會隨著尾鰭擺動頻率之增加而提高。尾鰭長度愈短之蝌蚪,增加游泳速度時尾鰭擺動頻率增加較多。蝌蚪游泳速度(V)與鰭長(SL)、擺動頻率(TBF)之迴歸方程式(V=0.480TBF+4.804SL-4.381,R2=0.9110)。不同尾鰭長度蝌蚪之擺幅對體長之比率並無明顯變化,其擺動幅度(AMP)的範圍介於0.45(BL)至0.56(BL)之間。蝌蚪游泳時各部分體軸之擺動幅度自吻端開始(P=0)至P 為0.24 時逐漸遞減,且在P 為0.24 時呈現最小擺幅,但P 超過0.24 之後直至尾鰭部分卻又大幅遞增,其最大值出現在尾鰭末端(P=1)。蝌蚪游泳是以尾鰭快速向中心軸擺動,產生較大的前進動力,過了軸線則慢速擺動,以減少阻力。This investigation is to explore the swimming habits of tadpoles- the relationship between their swimming velocity, length and height of their tails, mass, the frequency at which their tails movement, and the amplitude of the tail’s movement, as well as analysis their body axes, and the flow distribution of the water, in order to understand how the swimming patterns of the tadpoles are affected by the changes in their environment. The results of this investigation have shown that as the mass of the tadpoles increases, both the length and the height of their tails also increase according to the R values of the tail increases according to the R values of 0.9381 and 0.9809. However, it is observed the length of the tail increases at a faster rate than its height during the tadpoles’s growth. The formula which models the regression relationship between the tadpole’s mass, tail length, and tail height are found to be (M=0.027SL+0.342SH-0.078,R=0.9832). It’s also noted that as the length of the tadpole’s tail decreases, the velocity and the frequency of the tail would increases (the length of the tail is inversely proportional to the tadpole’s velocity and tail frequency). The formula which models the regression relationship between the tadpole’s velocity, tail length and tail frequency is (V=0.480TBF+4.804SL-4.381,R=0.9110) The different frequency model by tails of different lengths do not appear to have an apparent relationship with the tail length, given that the amplitude is between 0.45(BL) and 0.56(BL). As the tadpole swims, the angle between its oscillating body axes decrease as the P values increases from 0 to 0.24, their force the angle is at a minimum whom the P is at 0.24.Yet when P exceeds 0.24 the angle would increase dramatically. The maximum value is observed when P=1.The tadpole’s swimming motion mainly relays on the rapid oscillations of the tail about the centre of mass (body axis)-producing a stronger driving force, and slowing down towards the end of each oscillation to minimise the friction forces acting on the tadpole, which in furn, decrease its velocity.

長方體中切割正立方體之研究

在1940 年代,Bouwkamp 提出一系列有關如何將矩形切割成若干個正方形的研究報告,但是如何找出正方形個數最少的方法仍是長久以來懸而未決的問題。在本研究報告中,首先引進「四角切割」的方法,並結合輾轉相除法的概念,來研究矩形的切割問題。我們的方法能大幅度降低正方形的個數,也適合做為此問題的上界函數。有關如何在長方體中切割出正立方體的組合,我們也將輾轉相除法的概念延伸到三維空間,進而建立所切割出最少個正立體數的一個上界模式。此外,藉由四角切割概念的延伸,我們也發現這個上界亦可再予修正。In 1940’s, Bouwkamp proposed the study of dissecting squares from rectangles. Among the study, the problem of the least number of dissected squares has been open for decades. In this project, we first propose a corner dissection method, associated with the famous Euclidean algorithm. By reducing nearly three fourths of the number dissected by the primitive Euclidian algorithm, our method indeed establish a suitable upper bound of the minimal number of dissected squares from the given rectangles Meanwhile, the Euclidean algorithm has also been considered to dissect the cubes from cuboids. We analyze the fundamental properties of the method and establish a prototype of upper bound function for the minimal number of dissected cubes. Moreover, the method of corner dissection has also been implemented for some cuboids, which also exhibits the acceptable improvement being a suitable upper bound.

高中各學期成績與指定考科相關性

在升學主義越來越興盛的社會中,考試成績成為人人關心的重點,這\r 次研究就是藉由數理資優班同學的各學期在校成績和指定考科成\r 績,透過迴歸分析,找出各學期成績與指考成績之間的關係,並利用\r 圖表來解釋各種科目在各學期的課程,在高中三年所學的重要性,在\r 藉由此結果,希望能對目前老師的教育重點及學生學習方式能有所幫\r 助,亦可了解學生在高中求學過程中,哪些階段對指考成績較有正面\r 影響,進而強化該學習階段,以有助在指定考科時能充分發揮所學。\r \r In a society that emphasize on degrees, examination scores become the\r spotlight, and the ultimate goal for a high school student who had worked\r so hard for three years is to achieve high scores in the J.C.E.E. In the\r three years of high school, each subject has different topics each semester,\r but which semester has the most decisive effect on the J.C.E.E. score?\r This research is to study the effect of each semester on the J.C.E.E. by\r analyzing the grades of a science and math talented class in Senior High\r School using Regression analysis to find out the connections between\r term grades and the J.C.E.E. Then finding out which term grades had the\r most decisive effect in each subject. By using the result, we hope it can\r help teachers in their teaching and students in their learning. Also, it can\r provide the information about which stage in high school has positive\r effects on J.C.E.E. grades, therefore enabling students to emphasize on\r that stage in order to perform well on the J.C.E.E.

模擬聲波干涉

在高中光學裡,介紹了許多有關光波之特性,而聲波與光波皆具有波動性,因此聲波應具有如干涉、反射、聚焦等特性,但在物理課本上並未詳加敘述,所以我們開始了本項的研究,希望可以籍由改變聲源及邊界的各項條件,而探討其發生之現象。在本研究中,我們利用聲波之基本原理在電腦上進行聲場的模擬並加以改變其變因(頻率、相位、聲源數、聲源間距、強度、邊界反射),進而明瞭聲場之各項特性及應用與控制方式。經電腦模擬聲場圖中,我們觀察到,兩聲源干涉所形成之圖形為多組雙曲線所組成,近似於光學之雙狹縫干涉,增加聲音頻率與聲源間距離皆可使腹(節)線數目增加。如同現實世界中所知的,隨著頻率的增加,將會具有指向性的產生並且在聲源數目越多時越明顯,但發現頻率增加至一定值之後,指向性反而會降低而形成冠狀面。在延遲了多點聲源間相位之後,聲場分佈有偏轉之現象,利用相位延遲的方法,在多聲源中,將兩旁之聲音偏向中央將可造成聲音的聚焦。在兩聲源干涉中,調整其中一聲源之強度,將可完全消除兩音源連線間一點之聲音,可適當的應用在工業上消除噪音。聲場分佈在具有邊界的環境下,我們試著找出聲源位置及邊界條件對聲場分佈的影響與關係以模擬室內聲場,但在簡化的數學模式下,即無法有我們所希望之最均勻聲場分佈產生。最後我們將實驗中的結果與文獻上的實驗數據加以比較,以探討其誤差。 The optical course in senior high school , which introduced many characteristics of optical wave. However, both of sound and light have the characters of wave; therefore, sound wave should have the characteristics, such as interference, reflection and focalizing. Nevertheless, there are not many details of sound wave in the section of acoustic on our textbook. So we began this research, and discuss the different phenomena by changing many kinds of variables. In our research, we simulated the sound field on the computer, based on sound wave’s principle, furthermore we change many variables, which like frequency, phase, source number, distance, intensity and reflection. It helps us understand the characteristics of\r sound, how to control sound and how to apply these findings. According to the result of computer simulation, we discovered that the graph of two acoustic source’s interference comprised by many pairs of hyperbola, just like optical double slit interference. As the frequency or the sound source distance increased, acoustic direction became more and more obvious. But when the frequency was high enough to over the extreme, instead increasing, the acoustic direction would lower down like a crown. After we make phase differences on one of the two sound sources, sound field generated\r deviation. So if we use this method in multiple sound source, and delay the middle source, the sound field might be converged. In such two-sound-source interference pattern, when we control the intensity of one, a certainly point on the line of the two sources disappeared When the sound field enclose by borderline, the standing wave appear, and we discovered many funny phenomena. We put large amount of source in a narrow slit, the phenomenon of diffraction appeared. Finally, we discussed the discrepancies between interference pattern previously done by others experiments and the simulated one conducted by us.

紫蝶幻影

The main purpose of this experiment is to discuss the characteristics of iridescent colors of Taiwanese Euploea’s wings, inclusive of the relations between the colors of wings and squamas. According to the results from scanning electron microscope, we discovered that the iridescent colors had a close relation to nanostructure and arrangements of squamas. We inferred that both the nanostructure and the arrangements would influence the formation of iridescent colors and the basic colors on wings. In addition, the basic colors on wings are related to different types of scales. To compare with the diverse formations of different sorts of Taiwanese Euploea’s wings, we took SEM pictures of Elymnias hypermnestra as well, discovering that its iridescent colors had similar relation with scales. And there was the regulation that Elymnias hypermnestra had only one type of scales at iridescent area, and two different scales at not-iridescent area as well as Euploea’s. 本實驗目的為探討台灣地區紫斑蝶蝴蝶翅膀幻色的特性,以及翅膀幻色與鱗片的相關性。由結果得知,幻色實驗中利用掃描式電子顯微鏡發現紫斑蝶幻色的形成和其鱗片的細微結構與排列方式有密切相關。我們推論紫斑蝶的鱗片細微結構與排列皆會影響其幻色的形成,而顏色的不同則與不同類型的鱗片相關。除此之外,我們亦對同具幻色的紫蛇目碟進行拍照分析,發現其幻色亦與鱗片有相關性。紫蛇目蝶的幻色區具有單一種鱗片構成的規則性,非幻色區則有兩種鱗片,與紫斑蝶相同。

Is the fruit safe?-吊白塊的簡易自製試劑

吊白塊是一種在現切水果中常見的食品添加物,它可使剛切的水果不易被氧化,並同時具有漂白的效果,但此種添加物會對人體造成許多疾病。本研究針對吊白塊作嘗試性的初級檢驗,選用一般常見的氧化劑和染料,自行研發簡易的檢驗方法,且進一步製作安定性佳且攜帶方便的試紙。本實驗結果發現,由衛生局提供的「藍吊試劑」本身不甚穩定,且顏色變化不明顯;在自製檢驗試劑方面,效果最佳的是過錳酸鉀,濃度可測至0.0005M,且反應相當快速,唯試液容易與水果表面的Fe(II)離子反應;孔雀綠和晶紅酸等染料效果亦佳,且變色相當明顯,但反應時間較長。Rongalit is a bleaching agent commonly used as a food additive. It can prevent fresh fruits to be oxidized (without color-changed), especially when they were cut for sale. However, as for this additive, it is not good on health and is necessary to be detected. The test-paper currently used, the so-called “blue-test paper”, can be obtained from the Department of Health (Taipei). However, its stability is poor; the color change is not clear when it reacts with Rongalit. For this reason, I developed simple methods for detecting Rongalit by using various oxidizers and dyes. A test-paper, with better stability and easily for carry, was successfully developed. The findings show that the use of KMnO4 on the homemade test-paper provides the best result. The reaction time is short and the limit of detection can be improved to 5 × 10-4 M. The color changes were also clear when malachite green and fuchsin acid were used, but the reaction times were longer.

探討「避開矩形框」的配置方法與推廣

一、若Mn×n(s)表示在n×n 的正方形棋盤中,排列s 顆棋子在方格內,且每一方格最多只能排1子,其中s 顆棋子的配置需滿足兩個條件:1. 並無任意4 子可以形成矩形框的4 個頂點。(此矩形框的邊需與棋盤的邊平行)2. 在沒有棋子的方格中,無法再加入棋子。二、若Vn×n×n(a1,……,an) 表示在n×n×n 的正方體棋盤中,每層的棋子個數分別為a1,……,an,且s= a1+……+an,其中s 顆棋子的配置需滿足兩個條件:1. 並無任意8 子可以形成長方體的8 個頂點。(此長方體的邊需與立體棋盤的邊平行)2. 在沒有棋子的方格中,無法再加入棋子。本研究即在Mn×n(s)與Vn×n×n(a1,……,an) , s= a1+……+an 中探討s 的最小值、最大值及變化情形,並分析其配置方法。之後推廣至長方形Mn×m(s)及長方體Vn×m×k(a1,……,ak) , s= a1+……+ak。最後根據其研究結果設計一個「避開矩形框棋」,並加以分析出致勝的策略。一.If Mn×n(s) indicates in the n×n square chessboard, we put s chesses to line in the square and each square only can put one chess. Then the station of s chesses must satisfy the following two conditions:1. No any 4 chesses can form the tops of the rectangular frame ( The sides of rectangular frame must be parallel to the sides of chessboard )2. If there’s no chess in the square, we can’t add any chess. 二.If Mn×n×n(a1,……,an) indicates in the n×n×n square chessboard, the chess number in each layer are a1,……,an and s= a1+……+an. The station of s chesses must satisfy the following two conditions: 1. No any 8 chesses can form eight tops of the rectangular cube ( The sides of rectangular cube must be parallel to the sides of cubic chessboard ) 2. If there’s no chess in the square, we can’t add any chess. This research try to explore the minimum, maximum and variation of s which in Mn×n(s) and Mn×n×n(a1,……,an), s= a1+……+an, and analyze its station. Then we will extend the research to rectangle Mn×m(s) and rectangular cube Vn×m×k(a1,……,ak), s= a1+……+ak. Finally, according to the result of research we wish can design one “avert rectangular frame chess“ and analyze the strategies to triumph.

棋子排列的平均值

本研究由下述問題開始:將n1 個黑色棋子和n2 個白色棋子排成一列,規定第一個棋子必為黑棋;對於每一種排列方法中,同色棋相鄰處記為1,異色棋相鄰處記為-1,所有1 和-1 的總和記為 t (n1,n2 )。對所有可能的排列方法所算出來的t( n1,n2 ) 值求其平均值,記為a (n1,n2 ) 。我們先由觀察各種n1 和n2 值,得到這平均值的可能公式,隨後並嚴格證明其正確性,證明方法也經過多次精鍊到十分簡潔的方式。以此為基礎,我們並做了各方向的推廣,研究涉及下列各點:(一) 利用組合數探討原來的問題。(二) 在第一個棋子不限定為黑棋的假設下,求平均值a( n1,n2 ) 。(三) 將棋子由兩種增加到多種。(四) 改變棋子排列以及相鄰的方式。經由研究,我們發現,每一次愈將問題推廣時,愈能找出清晰的概念涵蓋並印證先前的想法。Our study starts with the following problem. Suppose n1 black chesses and n2 white chesses are arranged in a line under the condition that the first chess is black. For any arrangement of these chesses, an adjacent pair of chesses having the same (respectively, different) colors is associated with a value of 1 (respectively, -1). Let t(n1,n2 ) denote the sum of these values. The purpose of this problem is to calculate the average value a (n1,n2 ) of these t (n1,n2 )which runs over all possible arrangements of the chesses described above. We begin from observing various values of n1 and n2 and find a possible formula for the solution. We then give a rigorous proof for the formula. After some refinements, simple proofs are also established. Based on this, we also make some generalizations. In summary, the research includes the following: 1. Study the problem by using binomial coefficients. 2. Calculate a(n1,n2 ) when t( n1,n2 ) runs over all possible arrangements in which the first chess can be black or white. 3. Increase the types of chesses from two to many. 4. Variant the arrangement method of the chesses from a line to other configurations. During the study, we find that whenever we extend the problem to a more general case, we make the ideas for the original problem clearer.