臺灣

由於結網性蜘蛛視覺不靈敏，如何在網上藉振動進行獵捕，這是長久以來頗令科學家困惑的難題，當周遭環境各種振源觸網時，首先會產生不同振盪，蜘蛛是否藉由這些振盪得知獵物資訊？如何迅速準確的定位？又有那些決策條件影響蜘蛛的捕獵行為？更特別的，為何蜘蛛在捕獵過程中會“扯網”？本研究以台灣最大型結網性蜘蛛－人面蜘蛛為研究對象，並設計出一套非接觸式的測量方法，就上述謎題作深入的探討後，成功的解開人面蜘蛛的捕獵機制。簡單來說，其機制分為兩大系統：(1)當獵物擾動不明顯，人面蜘蛛會立即扯網，藉有無產生阻尼振盪，以判斷有無獵物存在；在阻尼振盪產生時，蜘蛛將感知其中具有最大阻尼振盪之放射絲為獵物所在方向，而振盪週期長短，係蜘蛛用以判斷獵物遠近之有效因素。(2)當振源明顯時，蜘蛛直接判斷各種擾動的振幅大小、頻率高低、波形模式、振源質量輕重，決定是否啟動捕獵或逃離反應，並在反應前先行定位，亦即以步足腳勾偵測並比較各放射絲之振盪大小，以振盪最大之放射絲為獵物方向，其次藉由第二對步足之位移所產生之準光角，判斷獵物之遠近。蜘蛛正確的將獵物定位後，會以適當的速度往前衝，一口咬住獵物，以蛛絲重重包裹後，拖往網中央並進行吸食。 Giant wood spider, Nephila pilipes, is the biggest orb web spider in Taiwan. The mature N. pilipes may even grow to exceed 5 cm body length. While waiting for the prey, its giant body hangs quietly on the hub of the web. Owing to its ineffective vision and sense of smell, the spider depends almost on detecting the vibration signal of the struggling of web cause by the struggling prey. When various kinds of sources from the environment contact the web, they will generate various types of vibrations which cause the spider to judge whether they represent danger, prey, or irrelevant signals. Our results suggest that if the disturbance is obvious, through discriminating the amplitude and frequency of the vibration, the spider will make a decision whether to attack or escape immediately. Yet, before any decision is made, it will need to locate the source of vibration. For example, it will locate prey correctly by comparing the vibration transmitted from the radiating strings. The radiating strings that transmitted the largest vibration are where the prey is entangled. The displacement of the second pair of legs will generate a quasi visual angle which enables it to comprehend the distance of prey. When the vibration signal is obscure, it will jerk the radiating string immediately. After jerking it, if there is damping oscillation on the web, then the spider can judge the location of the prey. When there is damping oscillation, the radiating string that transmitted the greatest damping oscillation is where the prey is entangled. Furthermore, the frequency of damping oscillation helps the spider to judge the distance of the prey. After locating the prey correctly, N. pilipes approaches the prey fast, wraps it with silk then drags the prey to the hub to feed.\r

The main purpose of this experiment is to discuss the characteristics of iridescent colors of Taiwanese Euploea’s wings, inclusive of the relations between the colors of wings and squamas. According to the results from scanning electron microscope, we discovered that the iridescent colors had a close relation to nanostructure and arrangements of squamas. We inferred that both the nanostructure and the arrangements would influence the formation of iridescent colors and the basic colors on wings. In addition, the basic colors on wings are related to different types of scales. To compare with the diverse formations of different sorts of Taiwanese Euploea’s wings, we took SEM pictures of Elymnias hypermnestra as well, discovering that its iridescent colors had similar relation with scales. And there was the regulation that Elymnias hypermnestra had only one type of scales at iridescent area, and two different scales at not-iridescent area as well as Euploea’s. 本實驗目的為探討台灣地區紫斑蝶蝴蝶翅膀幻色的特性，以及翅膀幻色與鱗片的相關性。由結果得知，幻色實驗中利用掃描式電子顯微鏡發現紫斑蝶幻色的形成和其鱗片的細微結構與排列方式有密切相關。我們推論紫斑蝶的鱗片細微結構與排列皆會影響其幻色的形成，而顏色的不同則與不同類型的鱗片相關。除此之外，我們亦對同具幻色的紫蛇目碟進行拍照分析，發現其幻色亦與鱗片有相關性。紫蛇目蝶的幻色區具有單一種鱗片構成的規則性，非幻色區則有兩種鱗片，與紫斑蝶相同。

在高中光學裡，介紹了許多有關光波之特性，而聲波與光波皆具有波動性，因此聲波應具有如干涉、反射、聚焦等特性，但在物理課本上並未詳加敘述，所以我們開始了本項的研究，希望可以籍由改變聲源及邊界的各項條件，而探討其發生之現象。在本研究中，我們利用聲波之基本原理在電腦上進行聲場的模擬並加以改變其變因（頻率、相位、聲源數、聲源間距、強度、邊界反射），進而明瞭聲場之各項特性及應用與控制方式。經電腦模擬聲場圖中，我們觀察到，兩聲源干涉所形成之圖形為多組雙曲線所組成，近似於光學之雙狹縫干涉，增加聲音頻率與聲源間距離皆可使腹(節)線數目增加。如同現實世界中所知的，隨著頻率的增加，將會具有指向性的產生並且在聲源數目越多時越明顯，但發現頻率增加至一定值之後，指向性反而會降低而形成冠狀面。在延遲了多點聲源間相位之後，聲場分佈有偏轉之現象，利用相位延遲的方法，在多聲源中，將兩旁之聲音偏向中央將可造成聲音的聚焦。在兩聲源干涉中，調整其中一聲源之強度，將可完全消除兩音源連線間一點之聲音，可適當的應用在工業上消除噪音。聲場分佈在具有邊界的環境下，我們試著找出聲源位置及邊界條件對聲場分佈的影響與關係以模擬室內聲場，但在簡化的數學模式下，即無法有我們所希望之最均勻聲場分佈產生。最後我們將實驗中的結果與文獻上的實驗數據加以比較，以探討其誤差。 The optical course in senior high school , which introduced many characteristics of optical wave. However, both of sound and light have the characters of wave; therefore, sound wave should have the characteristics, such as interference, reflection and focalizing. Nevertheless, there are not many details of sound wave in the section of acoustic on our textbook. So we began this research, and discuss the different phenomena by changing many kinds of variables. In our research, we simulated the sound field on the computer, based on sound wave’s principle, furthermore we change many variables, which like frequency, phase, source number, distance, intensity and reflection. It helps us understand the characteristics of\r sound, how to control sound and how to apply these findings. According to the result of computer simulation, we discovered that the graph of two acoustic source’s interference comprised by many pairs of hyperbola, just like optical double slit interference. As the frequency or the sound source distance increased, acoustic direction became more and more obvious. But when the frequency was high enough to over the extreme, instead increasing, the acoustic direction would lower down like a crown. After we make phase differences on one of the two sound sources, sound field generated\r deviation. So if we use this method in multiple sound source, and delay the middle source, the sound field might be converged. In such two-sound-source interference pattern, when we control the intensity of one, a certainly point on the line of the two sources disappeared When the sound field enclose by borderline, the standing wave appear, and we discovered many funny phenomena. We put large amount of source in a narrow slit, the phenomenon of diffraction appeared. Finally, we discussed the discrepancies between interference pattern previously done by others experiments and the simulated one conducted by us.

本研究旨在探討海藻酸鈉、澱粉及兩者混和成膜的特性，並討論上述薄膜添加氯化鈣進行交聯後對薄膜特性的影響及應用，希望將薄膜進一步應用在生活中。研究發現支鏈澱粉含量多所組成的薄膜，黏性高、易破、厚度最薄；添加澱粉量愈多的薄膜愈硬脆，若提高海藻酸鈉濃度可使膜較為平整柔軟；與氯化鈣交聯成膜則會使薄膜厚度增加、面積縮小；添加澱粉的海藻酸鈣薄膜吸水率提高，3%糯米粉乾粉混合膜的吸水率達99%最高，薄膜乾燥前期的含水率下降速率較快，將此薄膜重複吸水，第一次吸水量最高，之後的吸水量減低且往復吸水、乾燥的速率提高，將薄膜添加水晶寶寶可使吸水量增加製成吸水墊，以期取代目前生鮮食材用的PE淋膜不織布吸水紙，將能更具環保價值。

本研究由下述問題開始：將n1 個黑色棋子和n2 個白色棋子排成一列，規定第一個棋子必為黑棋；對於每一種排列方法中，同色棋相鄰處記為1，異色棋相鄰處記為-1，所有1 和-1 的總和記為 t (n1,n2 )。對所有可能的排列方法所算出來的t( n1,n2 ) 值求其平均值，記為a (n1,n2 ) 。我們先由觀察各種n1 和n2 值，得到這平均值的可能公式，隨後並嚴格證明其正確性，證明方法也經過多次精鍊到十分簡潔的方式。以此為基礎，我們並做了各方向的推廣，研究涉及下列各點：(一) 利用組合數探討原來的問題。(二) 在第一個棋子不限定為黑棋的假設下，求平均值a( n1,n2 ) 。(三) 將棋子由兩種增加到多種。(四) 改變棋子排列以及相鄰的方式。經由研究，我們發現，每一次愈將問題推廣時，愈能找出清晰的概念涵蓋並印證先前的想法。Our study starts with the following problem. Suppose n1 black chesses and n2 white chesses are arranged in a line under the condition that the first chess is black. For any arrangement of these chesses, an adjacent pair of chesses having the same (respectively, different) colors is associated with a value of 1 (respectively, -1). Let t(n1,n2 ) denote the sum of these values. The purpose of this problem is to calculate the average value a (n1,n2 ) of these t (n1,n2 )which runs over all possible arrangements of the chesses described above. We begin from observing various values of n1 and n2 and find a possible formula for the solution. We then give a rigorous proof for the formula. After some refinements, simple proofs are also established. Based on this, we also make some generalizations. In summary, the research includes the following: 1. Study the problem by using binomial coefficients. 2. Calculate a(n1,n2 ) when t( n1,n2 ) runs over all possible arrangements in which the first chess can be black or white. 3. Increase the types of chesses from two to many. 4. Variant the arrangement method of the chesses from a line to other configurations. During the study, we find that whenever we extend the problem to a more general case, we make the ideas for the original problem clearer.

從遊玩Dots and Boxes中3×3的遊戲設定中發現必勝法，藉此推廣其方法至大小2×n的的狀況下，尋找其中的相關規律。

吊白塊是一種在現切水果中常見的食品添加物，它可使剛切的水果不易被氧化，並同時具有漂白的效果，但此種添加物會對人體造成許多疾病。本研究針對吊白塊作嘗試性的初級檢驗，選用一般常見的氧化劑和染料，自行研發簡易的檢驗方法，且進一步製作安定性佳且攜帶方便的試紙。本實驗結果發現，由衛生局提供的「藍吊試劑」本身不甚穩定，且顏色變化不明顯；在自製檢驗試劑方面，效果最佳的是過錳酸鉀，濃度可測至0.0005M，且反應相當快速，唯試液容易與水果表面的Fe(II)離子反應；孔雀綠和晶紅酸等染料效果亦佳，且變色相當明顯，但反應時間較長。Rongalit is a bleaching agent commonly used as a food additive. It can prevent fresh fruits to be oxidized (without color-changed), especially when they were cut for sale. However, as for this additive, it is not good on health and is necessary to be detected. The test-paper currently used, the so-called “blue-test paper”, can be obtained from the Department of Health (Taipei). However, its stability is poor; the color change is not clear when it reacts with Rongalit. For this reason, I developed simple methods for detecting Rongalit by using various oxidizers and dyes. A test-paper, with better stability and easily for carry, was successfully developed. The findings show that the use of KMnO4 on the homemade test-paper provides the best result. The reaction time is short and the limit of detection can be improved to 5 × 10-4 M. The color changes were also clear when malachite green and fuchsin acid were used, but the reaction times were longer.

本研究首先探討台灣各地的日照時數與世界重要都市的比較，發現台灣南部日照時數皆超過2000 小時，適合發展太陽能。接著，?了增加陽光的能量密度而加設弗瑞奈透鏡，雖然能順利的使照度放大三百餘倍，但歲日照角度的影響甚鉅，?了克服角度的問題，我們決定開發自製的追蹤器來改善角度的問題。太陽能板需要改變仰角跟傾角（雙軸調整），由光感應器判斷及自動控制程式，判斷隨時辰與季節變化的太陽角度。當搭配奈米塗料、弗瑞奈透鏡與追蹤器，總輸出功率可增加約50%。太陽電池表面玻璃會阻擋藍紫光的吸收，但本研究在太陽能板上塗佈奈米塗料，發現能增加短波長的吸收；經實驗後奈米等級表面具有自潔效應，可防止灰塵雨滴的堆積影響光線吸收，具有開發價值。This project first compares Taiwanese locations with other places in the world on average daylight times. It was discovered that southern Taiwan has the longest average daylight time all over 2000 hour sand therefore most ripe for solar power development. To increase the energy density of solar Fresnel lenses were incorporated. Although this has the advantage of magnifying illumination by three hundred percent, the alignment angle for the solar panel will have a significant impact on performance. We then designed and built a automated tracking device with illumination sensors to control the elevation and inclination of the solar panel which adjusts the angle according to environmental conditions such as time of day and season. When solar cell collocate Nano coating, Fresnel lens, tracking device, its power can promote almost150%. The glasses on the solar cell will interfere solar cell absorbing blue and purple light, but we lay on a Nano coating and we find Nano coating can improve solar cell to absorb short wave; and surface o Nano have lotus effect, it can prevent dust and rain effecting solar cell absorb lights, and it is worth developing .

給定一平面E，A為平面上一點。取r>0，則我們知道到其距離為定值的點形成一圓，而A為此圓圓心。如果把A改成一平面圖形，則到其距離為定值的點形成的集合會是什麼樣子？類似地，給定平面上兩焦點F1及F2在平面上，則到其距離和為定值的點形成橢圓。同樣的，若把F1及F2改成平面圖形，其圖形會是什麼樣子？藉著GSP的輔助，到目前為止，我們得到了以下的結果： \r 1. 給定一平面E及此平面上的一個凸多邊形, 我們描繪出在此平面上到此凸多邊形之距離為定值的點所形成的圖形。\r 2. 設F1和F2分別為平面E上之點或線段或多邊形（未必是凸多邊形），我們利用包絡線描繪出所有滿足d(P,F1)+d(P,F2)=k（k夠大）的點所形成的圖形。 \r 3. 設C1,C2為平面E上之兩圓，我們討論所有滿足 d(P,C1)+d(P,C2)=k\r （k夠大）的點形成的圖形並討論其性質。 \r 4. 設L1和L2分別為平面E上之兩線段，我們討論所有滿足d(P,L1)+d(P,L2)=k（k夠大）的點形成的圖形並討論其性質。 \r 5. 設A為平面E上之一點，Γ為平面上一凸多邊形，我們討論所有滿足d(P,A)+D(P,Γ)=k（k夠大）的點形成的集合並討論其特性。 \r 6. 藉由和圓作比較，我們研究了變形圓的光學性質；而對變形橢圓也做類似的討論。\r Let E be a plane and A a fixed point on E. Given , it is known that all of the points on E with distance to 0r>rA form a circle and the point A is called the center of this circle. What is the corresponding graph if we replace the point A with a set (for example,a segament or a polygon) contained in FE? Similarly, what is the case when we modify the two focuses and in the definition of an ellcpse to sets and (or example,two segments or two polygons) contained in 1F2F1F2FE ? Taking advantages of GSP and analytic geomety, we research related situations and so far we have obtained the following results:\r 1. Let Γ?E be a segment, a convex polygon or a circle , etc. and r>0 be fixed. We sketch the graph of points on E with distance r to Γ and study properties of such graphs.\r 2. Let F1 and F2 be singletons, line segments , polygons(may not be convex), or circles,etc., on E Taking advantage of envelopes, we sketch the graph of those points P on E satisfying d(P,F1)=k(K>0 is large enough).\r 3. Let C1 and C2 be circles on 1C2CE. We sketch the graph of the points P on E that satisfiy d(P,C1)6d(P,C2)=k (k>0 is large enough) and study properties of this graph.\r 4. Let L1 and L2 be two line segments on E and be a large enough constant. We sketch the graph of points P on E that satisfy d(P,L1)+d(P,L2)=k(k >0is large enough) and research properties of this graph. 0k>\r 5. Let A?E and be a convex polygon on ΓE. We sketch the graph of points on E that satisfy d(P,L1)+d(P,L2)=k(k>0 is large enough) and research properties of this graph.\r 6.We compare the optical properties of metamorphic circles with circles and we deal with metamorphic ellipses similiarly.

一、若Mn×n(s)表示在n×n 的正方形棋盤中，排列s 顆棋子在方格內，且每一方格最多只能排1子，其中s 顆棋子的配置需滿足兩個條件：1. 並無任意4 子可以形成矩形框的4 個頂點。（此矩形框的邊需與棋盤的邊平行）2. 在沒有棋子的方格中，無法再加入棋子。二、若Vn×n×n(a1,……,an) 表示在n×n×n 的正方體棋盤中，每層的棋子個數分別為a1,……,an，且s= a1+……+an，其中s 顆棋子的配置需滿足兩個條件：1. 並無任意8 子可以形成長方體的8 個頂點。（此長方體的邊需與立體棋盤的邊平行）2. 在沒有棋子的方格中，無法再加入棋子。本研究即在Mn×n(s)與Vn×n×n(a1,……,an) , s= a1+……+an 中探討s 的最小值、最大值及變化情形，並分析其配置方法。之後推廣至長方形Mn×m(s)及長方體Vn×m×k(a1,……,ak) , s= a1+……+ak。最後根據其研究結果設計一個「避開矩形框棋」，並加以分析出致勝的策略。一．If Mn×n(s) indicates in the n×n square chessboard, we put s chesses to line in the square and each square only can put one chess. Then the station of s chesses must satisfy the following two conditions：1. No any 4 chesses can form the tops of the rectangular frame ( The sides of rectangular frame must be parallel to the sides of chessboard )2. If there’s no chess in the square, we can’t add any chess. 二．If Mn×n×n(a1,……,an) indicates in the n×n×n square chessboard, the chess number in each layer are a1,……,an and s= a1+……+an. The station of s chesses must satisfy the following two conditions： 1. No any 8 chesses can form eight tops of the rectangular cube ( The sides of rectangular cube must be parallel to the sides of cubic chessboard ) 2. If there’s no chess in the square, we can’t add any chess. This research try to explore the minimum, maximum and variation of s which in Mn×n(s) and Mn×n×n(a1,……,an), s= a1+……+an, and analyze its station. Then we will extend the research to rectangle Mn×m(s) and rectangular cube Vn×m×k(a1,……,ak), s= a1+……+ak. Finally, according to the result of research we wish can design one “avert rectangular frame chess“ and analyze the strategies to triumph.